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x^2+5x+6=x+2
We move all terms to the left:
x^2+5x+6-(x+2)=0
We get rid of parentheses
x^2+5x-x-2+6=0
We add all the numbers together, and all the variables
x^2+4x+4=0
a = 1; b = 4; c = +4;
Δ = b2-4ac
Δ = 42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-4}{2}=-2$
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